In the figure given below, A, B and C are points on OP, OQ and OR respectively such that AB || PQ and AC || PR. show that BC || QR.
Solution:
ABCD is a trapezium in which AB || DC and its diagonals intersect each other at O. Using Basic Proportionality theorem, prove that 
Solution:
More Solutions:
- DE parallel BC. If DE = 6 cm, BC = 9 cm and area of ∆ADE = 28 sq. cm
- Prove that ∆ADE and ∆ABC are similar.
- In the given figure, AB and DE are perpendicular to BC.
- In the adjoining figure, ABC is a triangle. DE is parallel to BC.
- In ∆ABC, AP: PB = 2 : 3. PO is parallel to BC and is extended to Q so that CQ is parallel to BA.
- Determine the ratio of the areas of ∆AOB and ∆COD.