A pole of height 5 m is fixed on the top of a tower.

A pole of height 5 m is fixed on the top of a tower. The angle of elevation of the top of the pole as observed from point A on the ground is 60° and the angle of depression of the point A from the top of the tower is 45°. Find the height of the tower. (Take √3 = 1.732).

Solution:

Let QR be the tower and PQ be the pole on it
Angle of elevation from P to a point A is ∠PAR = 60°
and angle of depression from Q to A = 45°
∠QAR = 45° (alternate angle)
PQ = 5 m,

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