#### A pole of height 5 m is fixed on the top of a tower. The angle of elevation of the top of the pole as observed from point A on the ground is 60° and the angle of depression of the point A from the top of the tower is 45°. Find the height of the tower. (Take √3 = 1.732).

**Solution:**

Let QR be the tower and PQ be the pole on it

Angle of elevation from P to a point A is ∠PAR = 60°

and angle of depression from Q to A = 45°

∠QAR = 45° (alternate angle)

PQ = 5 m,

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