**In the given figure, ABC is a right angled triangle at B. A semicircle is drawn on AB as diameter. If AB = 12 cm and BC = 5 cm, then the area of the shaded region is**

**(a) (60 + 18π) cm**^{2}

**(b) (30 + 36π) cm**^{2}

**(c) (30+18π) cm**^{2}

**(d) (30 + 9π) cm**^{2}

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**Solution:**

**The perimeter of the shaded region shown in Q. 16 (above) is**

**(a) (30 + 6π) cm**

**(b) (30 + 12π) cm**

**(c) (18 + 12π) cm**

**(d) (18 + 6π) cm**

**Solution:**

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