If ∆ABC ~ ∆QRP 
AB = 18 cm and BC = 15 cm, then the length of PR is equal to
(a) 10 cm
(b) 12 cm
(c) 
(d) 8 cm
Solution:
If ∆ABC ~ ∆PQR, area of ∆ABC = 81 cm², area of ∆PQR = 144 cm² and QR = 6 cm, then length of BC is
(a) 4 cm
(b) 4.5 cm
(c) 9 cm
(d) 12 cm
Solution:
More Solutions:
- CM and RN are respectively the medians of ∆ABC and ∆PQR.
- Medians AD and BE of ∆ABC meet at the point G.
- In the figure given below, AB, EF and CD are parallel lines.
- ∠A = 90° and AD ⊥ BC If BD = 2 cm and CD = 8 cm.
- A 15-meter high tower casts a shadow of 24 meters.
- In the figure, DE parallel BG, AD = 3 cm, BD = 4 cm and BC = 5 cm.