In the given figure, AB and CD are equal chords. AD and BC intersect at E. Prove that AE = CE and BE = DE.
Solution:
In the adjoining figure, O is the centre of the given circle and OABC is a parallelogram. BC is produced to meet the circle at D.
Prove that ∠ABC = 2 ∠OAD.
Solution:
More Solutions:
- Given below, AB is a diameter of a circle with centre O.
- P is the point of intersection of the chords BC and AQ.
- CP bisects ∠ACB. Prove that DP bisects ∠ADB.
- Given below, chords AB and CD of a circle intersect at E.
- AE and BC intersect each other at point D. If ∠CDE = 90°.
- Calculate the perimeter of the cyclic quadrilateral PQRS.