In the given figure, AB is a chord of the circle such that ∠ACB = 50°. If AT is tangent to the circle at the point A, then ∠BAT is equal to
(a) 65°
(b) 60°
(c) 50°
(d) 40°
Solution:
In the given figure, O is the centre of a circle and PQ is a chord. If the tangent PR at P makes an angle of 50° with PQ, then ∠POQ is
(a) 100°
(b) 80°
(c) 90°
(d) 75°
Solution:
More Solutions:
- A point P is 13 cm from the center of a circle.
- From a point outside a circle, with center O, tangents PA and PB are drawn.
- The figure given below shows two circles with centres A, B.
- Two circles with centers A and B touch externally.
- Two chords AB, CD of a circle intersect externally at a point P.
- Chord AB and diameter CD of a circle with centre O meet at P.