AB is a diameter of a circle. M is a point in AB such that AM = 18 cm and MB = 8 cm. Find the length of the shortest chord through M.
Solution:
More Solutions:
- In an equilateral triangle.
- Show that CA = 2 OD.
- If OE bisects ∠AED, Prove that AB = CD.
- AD is a diameter of a circle with centre O.
- Find the ratio of AB: CD.
- Prove that OC bisects the arc AB.
- Prove that the angle subtended.
- Prove that arc AD = arc CB.
- The line segment PQ is called a
- The circumference of a circle must be