ABCD is a rhombus such that ∠ACB = 40°. Then ∠ADB is
(a) 40°
(b) 45°
(c) 50°
(d) 60°
Solution:
More Solutions:
- Show that DAC=BCA
- Prove that the quadrilateral
- Find the size of each lettered angle in the Following Figures.
- Lettered angle in the following figures :
- If ∠ABC = 56°, find
- Find the lengths of its diagonals.
- Prove that ∠AEB is a right angle.
- Prove that the line segment
- Prove that the diagonals of a parallelogram.
- AD is median of ∆ABC and P.