AD = BD = DC and ∠ACD = 35°. Show that

(a) In the figure (1) given below, AD = BD = DC and ∠ACD = 35°. Show that
(i) AC > DC (ii) AB > AD.
(b) In the figure (2) given below, prove that
(i) x + y = 90° (ii) z = 90° (iii) AB = BC
ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 10 Triangles ch Q13.1

Solution:

ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 10 Triangles ch Q13.2
ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 10 Triangles ch Q13.3
ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 10 Triangles ch Q13.4
ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 10 Triangles ch Q13.5

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