(a) In the figure (i) given below, AD is a diameter of a circle with centre O.
If AB || CD, prove that AB = CD.
(b) In the figure (ii) given below, AB and CD are equal chords of a circle with centre O. If AB and CD meet at E (outside the circle) Prove that :
(i) AE = CE (ii) BE = DE.
Solution:
More Solutions:
- ABCD and AEFG are two parallelograms.
- prove that area of ∆ BCE
- Prove that area of rectangle ∆BCD
- Prove that area of ∆CEF = 38
- Prove that area of ∆ABE=area of ∆ACF.
- Calculate the lengths of the sides of the parallelogram.
- Find the area of || gm EBCF.
- Prove that: area of ∆ABC= area of ∆EBD.
- The correct statement is
- The ratio of their areas is