(a) In the figure (1) given below, AD is median of ∆ABC and P is any point on AD. Prove that
(i) area of ∆PBD = area of ∆PDC.
(ii) area of ∆ABP = area of ∆ACP.
(b) In the figure (2) given below, DE || BC. prove that (i) area of ∆ACD = area of ∆ ABE.
(ii) area of ∆OBD = area of ∆OCE.
Solution:
More Solutions:
- Prove that: Area of ∆ABP + area of ∆DPC = Area of ∆APD.
- Prove that area of quad.
- Prove that, area of ∆ CPD = area of ∆ AQD.
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- Prove that BCEF is a trapezium.
- Prove that two triangles having equal areas.
- Prove that area of ∆ ABD: area of ∆ ADC = m : n.
- Calculate the height of parallelogram.
- Prove that : area of ∆APQ = area of ∆DPQ = 16
- Prove that: area of || gm ABCD + area of || gm AEFB = area of || gm EFCD.