In the given figure, two circles touch each other at A. BC and AP are common tangents to these circles. If BP = 3.8 cm, then the length of BC is equal to
(a) 7.6 cm
(b) 1.9 cm
(c) 11.4 cm
(d) 5.7 cm
Solution:
In the given figure, if sides PQ, QR, RS and SP of a quadrilateral PQRS touch a circle at points A, B, C and D respectively, then PD + BQ is equal to
(a) PQ
(b) QR
(c) PS
(d) SR
Solution:
More Solutions:
- A point P is 13 cm from the center of a circle.
- From a point outside a circle, with center O, tangents PA and PB are drawn.
- The figure given below shows two circles with centres A, B.
- Two circles with centers A and B touch externally.
- Two chords AB, CD of a circle intersect externally at a point P.
- Chord AB and diameter CD of a circle with centre O meet at P.