In ∆ABC, ∠A is acute. BD and CE are perpendicular on AC and AB respectively. Prove that AB x AE = AC x AD.
Solution:
In the given figure, DB ⊥ BC, DE ⊥ AB and AC ⊥ BC. Prove that 
Solution:
More Solutions:
- Straight line passing through the intersection of 2x + 5y – 4 = 0.
- Line perpendicular from the point (1, -2) on the line 4x – 3y – 5 = 0.
- The line through (0, 0) and (2, 3) is parallel.
- The points A (1, 3), B (3, -1) and C (-5, -5) is a right-angled triangle.
- A (-1, 3), B (4, 2), C (3, -2) are the vertices of a triangle.
- In the adjoining diagram, the coordinates of the points A, B and C.