In the given figure, CM and RN are respectively the medians of ∆ABC and ∆PQR. If ∆ABC ~ ∆PQR, prove that:
(i) ∆AMC ~ ∆PNR
(ii)
(iii) ∆CMB ~ ∆RNQ.
Solution:
More Solutions:
- DE parallel BC. If DE = 6 cm, BC = 9 cm and area of ∆ADE = 28 sq. cm
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