Construct a triangle ABC with AB = 5.5 cm, AC = 6 cm, and ∠BAC = 105°. Hence:
(i) Construct the locus of points equidistant from BA and BC.
(ii) Construct the locus of points equidistant from B and C.
(iii) Mark the point which satisfies the above two loci as P. Measure and write the length of PC.
Solution:
In the given diagram, A, B and C are fixed collinear points; D is a fixed point outside the line: Locate
(i) the point P on AB such that CP = DP.
(ii) the points Q such that CQ = DQ = 3 cm. How many such points are possible?
(iii) the points R on AB such that DR = 4 cm. How many such points are possible?
(iv) the points S such that CS = DS and S is 4 cm away from the line CD. How many such points are possible?
(v) Are the points P, Q, R collinear?
(vi) Are the points P, Q, S collinear?
Solution:
More Solutions:
- Draw a circle of radius 4 cm and mark two chords AB and AC.
- Draw the locus of all points which are equidistant from A and B.
- Construct the locus of a point P such that area of triangle PAB is 14 cm².
- AB and CD are two intersecting lines.
- Construct a rhombus PQRS whose diagonals PR, QS are 8 cm and 6 cm.
- By using ruler and compass only, construct a quadrilateral ABCD.