The perpendicular distances between the pairs of opposite sides of a parallelogram ABCD are 3 cm and 4 cm and one of its angles measures 60°. Using ruler and compasses only, construct ABCD.
Solution:
More Solutions:
- Measure its sides correct to the nearest millimeter.
- Construct A rhombus ABCD given that AB 5cm.
- Measure ∠ABC.
- Whose diagonals PR and QS.
- ABCD of side 4.6 cm and ∠BCD = 135°
- The distance between parallel sides is 2.9 cm.
- When one of parallel sides AB = 4.8 cm.
- Construct a regular hexagon of side 2.5 cm.
- The fourth angle is
- If PQRS is a parallelogram