#### An aircraft is flying at a constant height with a speed of 360 km/h. From a point on the ground, the angle of elevation of the aircraft at an instant was observed to be 45°. After 20 seconds, the angle of elevation was observed to be 30°. Determine the height at which the aircraft is flying (use √3 = 1.732)

**Solution:**

Speed of aircraft = 360 km/h

Distance covered in 20 seconds = = 2 km

E is the fixed point on the ground

and CD is the position of AB in height of aircraft

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