The figure formed by joining the midpoints of the sides of a quadrilateral ABCD, taken in order, is a square only if
(a) ABCD is a rhombus r
(b) diagonals of ABCD are equal
(c) diagonals of ABCD are perpendicular to each other
(d) diagonals of ABCD are equal and perpendicular to each other.
Solution:
More Solutions:
- Write the length of its hypotenuse:
- Find the height of the point on the wall.
- How far from the base of the pole.
- Find the distance between their tops.
- The ratio of the other two sides is 4:3.
- Prove that it is right-angled triangle.
- Find the sides of the triangle.
- Prove that AB² = 2AC².
- Prove that AB² + CD² = AC² + BD².
- Prove that (a + b) (a – b) = (c + d) (c – d).