(a) In the figure (1) given below, E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. show that ∆ABE ~ ∆CFB.
(b) In the figure (2) given below, PQRS is a parallelogram; PQ = 16 cm, QR = 10 cm. L is a point on PR such that RL : LP = 2 : 3. QL produced meets RS at M and PS produced at N.
(i) Prove that triangle RLQ is similar to triangle PLN. Hence, find PN.
(ii) Name a triangle similar to triangle RLM. Evaluate RM.
Solution:
More Solutions:
- Straight line passing through the intersection of 2x + 5y – 4 = 0.
- Line perpendicular from the point (1, -2) on the line 4x – 3y – 5 = 0.
- The line through (0, 0) and (2, 3) is parallel.
- The points A (1, 3), B (3, -1) and C (-5, -5) is a right-angled triangle.
- A (-1, 3), B (4, 2), C (3, -2) are the vertices of a triangle.
- In the adjoining diagram, the coordinates of the points A, B and C.