#### Evaluate x^{1/2}. y^{-1}. z^{2/3} when x = 9, y = 2 and z = 8.

**Solution:**

It is given that

x = 9, y = 2 and z = 8

We know that

x^{1/2}. y^{-1}. z^{2/3} = (9)^{1/2}. (2)^{-1}. (8)^{2/3}

= 6

**More Solutions:**

- Simplify the following: (i) (81/16)-3/4.
- Simplify the following : (i) (2a-3b2)3
- Simplify the following: (i) 3a/b-1 + 2b/a-1
- Simplify the following: (i) (8/125)-1/3
- Simplify the following : (i) (-1/27)-2/3
- Simplify the following Indices:
- Evaluate the following indices:
- Simplify the following:(i) (3×2)-3 × (x9)2/3
- Simplify the following: (i) (32)0 + 3-4 × 36 + (1/3)-2