(i) (5x – 3y)3
(ii) (2x – 1/3y)3
Answer :
(i) (5x – 3y)3
It can be written as
= (5x)3 – (3y)3 – 3 × 5x × 3y (5x – 3y)
By further calculation
= 125x3 – 27y3 – 45xy (5x – 3y)
So we get
= 125x3 – 27y3 – 225x2y + 135xy2
(ii) (2x – 1/3y)3
It can be written as
= (2x)3 – (1/3y)3 – 3 × 2x × 1/3y (2x – 1/3y)
By further calculation
= 8x3 – 1/27y3 – 2x/y (2x – 1/3y)
So we get
= 8x3 – 1/27y3 – 4x2/y + 2x/3y2
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