(i) (x + 3) (x + 5)
(ii) (x + 3) (x – 5)
(iii) (x – 7) (x + 9)
(iv) (x – 2y) (x – 3y)
Answer :
(i) (x + 3) (x + 5)
By further calculation
= x2 + (3 + 5) x + 3 × 5
So we get
= x2 + 8x + 15
(ii) (x + 3) (x – 5)
By further calculation
= x2 + (3 – 5)x – 3 × 5
So we get
= x2 – 2x – 15
(iii) (x – 7) (x + 9)
By further calculation
= x2 – (7 – 9)x – 7 × 9
So we get
= x2 + 2x – 63
(iv) (x – 2y) (x – 3y)
By further calculation
= x2 – (2y + 3y)x + 2y × 3y
So we get
= x2 – 5xy + 6y2
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