(i) (x + 2)3
(ii) (2a + b)3
Answer :
(i) (x + 2)3
It can be written as
= x3 + 23 + 3 × x × 2 (x + 2)
By further calculation
= x3 + 8 + 6x (x + 2)
So we get
= x3 + 8 + 6x2 + 12x
= x3 + 6x2 + 12x + 8
(ii) (2a + b)3
It can be written as
= (2a)3 + b3 + 3 × 2a × b (2a + b)
By further calculation
= 8a3 + b3 + 6ab (2a + b)
So we get
= 8a3 + b3 + 12a2b + 6ab2
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