Factories the following :
(i) 8xy3 + 12x2y2
(ii) 15 ax3 – 9ax2
Sol: (i) 8xy3 + 12x2y2
Take out common in both terms,
Then, 4xy2 (2y + 3x)
Therefore, HCF of 8xy3 and 12x2y2 is 4xy2.
(ii) 15 ax3 – 9ax2
Take out common in both terms,
Then, 3ax2 (5x – 3)
Therefore, HCF of 15 ax3 and 9ax2 is 3ax2.
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