**(i) 1 – a – b + ab**

**(ii) a(a – 2b – c) + 2bc**

**Answer :**

**(i) 1 – a – b + ab**

Take out common in all terms,

1(1 – a) – b(1 – a)

(1 – a) (1 – b)

**(ii) a(a – 2b – c) + 2bc**

a(a – 2b – c) + 2bc

Above question can be written as,

a^{2} – 2ab – ac + 2bc

Take out common in all terms,

a(a – 2b) – c(a + 2b)

(a – 2b) (a – c)

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