(i) 21py2 – 56py
(ii) 4x3 – 6x2
Sol: (i) 21py2 – 56py
Take out common in both terms,
Then, 7py (3y – 8)
Therefore, HCF of 21py2 and 56py is 7py.
(ii) 4x3 – 6x2
4x3 – 6x2
Take out common in both terms,
Then, 2x2 (2x – 3)
Therefore, HCF of 4x3 and 6x2 is 2x2.
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