(i) 2a2b2 – 7ab – 30
(ii) a(2a – b) – b2
Answer :
(i) 2a2b2 – 7ab – 30
2a2b2 – 12ab + 5ab – 30
Take out common in all terms we get,
2ab(ab – 6) + 5 (ab – 6)
(ab – 6) (2ab + 5)
(ii) a(2a – b) – b2
a(2a – b) – b2
Above terms can be written as,
2a2 – ab – b2
2a2 – 2ab + ab – b2
Take out common in all terms we get,
2a(a – b) + b(a – b)
(a – b) (2a + b)
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