(i) 2a2x – bx + 2a2 – b
(ii) p2 – (a + 2b)p + 2ab
Answer :
(i) 2a2x – bx + 2a2 – b
Rearrange the above terms we get,
2a2x + 2a – bx – b
Take out common in both terms,
2a2(x + 1) – b(x + 1)
(x + 1) (2a2 – b)
(ii) p2 – (a + 2b)p + 2ab
p2 – (a + 2b)p + 2ab
Above terms can be written as,
p2 – ap – 2bp + 2ab
Take out common in both terms,
p(p – a) – 2b(p – a)
(p – a) (p – 2b)
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