Factorise 2πr2 – 4πr

(i) 2πr2 – 4πr

(ii) 18m + 16n

Sol: (i) 2πr2 – 4πr

Take out common in both terms,

Then, 2πr (r – 2)

Therefore, HCF of 2πr2 and 4πr is 2πr.

(ii) 18m + 16n

18m + 16n

Take out common in both terms,

Then, 2 (9m + 8n)

Therefore, HCF of 18m and 16n is 2.

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