(i) 2πr2 – 4πr
(ii) 18m + 16n
Sol: (i) 2πr2 – 4πr
Take out common in both terms,
Then, 2πr (r – 2)
Therefore, HCF of 2πr2 and 4πr is 2πr.
(ii) 18m + 16n
18m + 16n
Take out common in both terms,
Then, 2 (9m + 8n)
Therefore, HCF of 18m and 16n is 2.
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