**(i) 2(x – 2y) ^{2} – 50y^{2}**

**(ii) 32 – 2(x – 4) ^{2}**

**Answer :**

**(i) 2(x – 2y)**^{2} – 50y^{2}

^{2}– 50y

^{2}

Take out common in all terms,

2[(x – 2y)^{2} – 25y^{2}]

2[(x – 2y)^{2} – (5y)^{2}]

We know that, a^{2} – b^{2} = (a + b) (a – b)

2[(x – 2y + 5y) (x – 2y – 5y)]

2[(x + 3y) (x – 7y)]

2(x + 3y) (x – 7y)

**(ii) 32 – 2(x – 4)**^{2}

^{2}

32 – 2(x – 4)^{2}

Take out common in all terms,

2[16 – (x – 4)^{2}]

2[4^{2}– (x – 4)^{2}]

We know that, a^{2} – b^{2} = (a + b) (a – b)

2[(4 + x – 4) (4 – x + 4)]

2[(x) (8 – x)]

2x (8 – x)

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