Factorise (2x – y)2 – 11(2x – y) + 28

(i) (x – y)2 – 6(x – y) + 5

(ii) (2x – y)2 – 11(2x – y) + 28

Answer :

(i) (x – y)2 – 6(x – y) + 5

Above terms can be written as,

(x – y)2 – 5(x – y) – (x – y) + 5

(x – y) (x – y – 5) – 1(x – y – 5)

Then,

(x – y – 5) (x – y – 1)

(ii) (2x – y)2 – 11(2x – y) + 28

(2x – y)2 – 11(2x – y) + 28

Above terms can be written as,

(2x – y)2 – 7(2x – y) – 4(2x – y) + 28

(2x – y) (2x – y – 7) – 4(2x – y – 7)

(2x – y – 7) (2x – y – 4)

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