(i) 2x2 + 13xy – 24y2
(ii) 6x2 – 5xy – 6y2
Answer :
(i) 2x2 + 13xy – 24y2
2x2 + 16xy – 3xy – 24y2
Take out common in all terms we get,
2x(x + 8y) – 3y(x + 8y)
(x + 8y) (2x – 3y)
(ii) 6x2 – 5xy – 6y2
6x2 – 5xy – 6y2
6x2 – 9xy + 4xy – 6y2
Take out common in all terms we get,
3x(2x – 3y) + 2y (2x – 3y)
(2x – 3y) (3x + 2y)
More Solutions:
- Factorise 2a2b2 – 7ab – 30
- Factorise (x – y)2 – 6(x – y) + 5
- Factorise 4(a – 1)2 – 4(a – 1) – 3
- Factorise 3 – 5a – 5b – 12(a + b)2
- Factorise (x + 4)2 – 5xy -20y – 6y2
- Factorise 4(2a – 3)2 – 3(2a – 3) (a – 1) – 7 (a – 1)2
- Factorise (2×2 + 5x) (2×2 + 5x – 19) + 84
- Factorise x2 – 8x + 7
- Factorise y2 + 7y – 18
- Factorise a2 – 3a – 54