**(i) 2x ^{4} – 32**

**(ii) a ^{2}(b + c) – (b + c)^{3}**

**Answer:**

**(i) **2**x**^{4} – 32

^{4}– 32

Take out common in all terms,

2(x^{4} – 16)

Above terms can be written as,

2((x^{2})^{2} – 4^{2})

We know that, a^{2} – b^{2} = (a + b) (a – b)

2(x^{2} + 4) (x^{2} – 4)

2(x^{2} + 4) (x^{2} – 2^{2})

2(x^{2} + 4) (x + 2) (x – 2)

**(ii) a**^{2}(b + c) – (b + c)^{3}

^{2}(b + c) – (b + c)

^{3}

a^{2}(b + c) – (b + c)^{3}

Take out common in all terms,

(b + c) (a^{2} – (b + c)^{2})

We know that, a^{2} – b^{2} = (a + b) (a – b)

(b + c) (a + b + c) (a – b – c)

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