Factorise (3a – 2b)2 + 3(3a – 2b) – 10

(3a – 2b)² + 3(3a – 2b) – 10

Let us assume, (3a – 2b) = p

p² + 3p – 10

p² + 5p – 2p – 10

Take out common in all terms,

p(p + 5) – 2(p + 5)

(p + 5) (p – 2)

Now, substitute the value of p

(3a – 2b + 5) (3a – 2b – 2)