Factorise 4(2a – 3)2 – 3(2a – 3) (a – 1) – 7 (a – 1)2

4(2a – 3)² – 3(2a – 3) (a – 1) – 7 (a – 1)²

Answer :

4(2a – 3)² – 3(2a – 3) (a – 1) – 7 (a – 1)²

Let us assume, 2a – 3 = p and a – 1 = q

So, 4p² – 3pq – 7q²

Then, 4p² – 7pq + 4pq – 7q²

Take out common in all terms we get,

P(4p – 7q) + q(4p – 7q)

(4p – 7q) (p + q)

Now, substitute the value of p and q we get,

(4(2a – 3) – 7(a – 1)) (2a – 3 + a – 1)

(8a – 12 – 7a + 7) (3a – 4)

(a – 5) (3a – 4)

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