(i) 5ph – 10qk + 2rph – 4qrk
(ii) x2 – x(a + 2b) + 2ab
Answer :
(i) 5ph – 10qk + 2rph – 4qrk
Re-arranging the given question we get,
5ph + 2rph – 10qk – 4qrk
Take out common in all terms,
ph(5 + 2r) – 2qk(5 + 2r)
(5 + 2r) (ph – 2qk)
(ii) x2 – x(a + 2b) + 2ab
x2 – x(a + 2b) + 2ab
Above question can be written as,
x2 – xa – 2xb + 2ab
Take out common in all terms,
x(x – a) – 2b(x – a)
(x – a) (x – 2b)
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