(8/27)x3 – (1/8)y3
Above terms can be written as,
((2/3)x)3 – (½y)3
We know that, a3 – b3 = (a – b) (a2 + ab + b2)
((2/3)x – ½y) [(2/3)x + (2/3)x (1/2)y + ((1/2)y)2]
((2/3)x – (1/2)y) [(4/9)x2 + (xy/3) + (y2/4)]
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Above terms can be written as,
((2/3)x)3 – (½y)3
We know that, a3 – b3 = (a – b) (a2 + ab + b2)
((2/3)x – ½y) [(2/3)x + (2/3)x (1/2)y + ((1/2)y)2]
((2/3)x – (1/2)y) [(4/9)x2 + (xy/3) + (y2/4)]