Factorise a3 + ab(1 – 2a) – 2b2

(i) a³ + ab(1 – 2a) – 2b²

(ii) 3x²y – 3xy + 12x – 12

Answer:

(i) a³ + ab(1 – 2a) – 2b²

Above question can be written as,

a³ + ab – 2a²b – 2b²

Re-arranging the above we get,

a³ – 2a²b + ab – 2b²

Take out common in all terms,

a²(a – 2b) + b(a – 2b)

(a – 2b) (a² + b)

(ii) 3x²y – 3xy + 12x – 12

3x²y – 3xy + 12x – 12

Take out common in all terms,

3xy(x – 1) + 12(x – 1)

(x – 1) (3xy + 12)

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