#### (i) a^{3} + ab(1 – 2a) – 2b^{2}

#### (ii) 3x^{2}y – 3xy + 12x – 12

**Answer:**

**(i)** **a**^{3} + ab(1 – 2a) – 2b^{2}

^{3}+ ab(1 – 2a) – 2b

^{2}

Above question can be written as,

a^{3} + ab – 2a^{2}b – 2b^{2}

Re-arranging the above we get,

a^{3} – 2a^{2}b + ab – 2b^{2}

Take out common in all terms,

a^{2}(a – 2b) + b(a – 2b)

(a – 2b) (a^{2} + b)

**(ii) 3x**^{2}y – 3xy + 12x – 12

^{2}y – 3xy + 12x – 12

3x^{2}y – 3xy + 12x – 12

Take out common in all terms,

3xy(x – 1) + 12(x – 1)

(x – 1) (3xy + 12)

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