(i) (x + 4)2 – 5xy -20y – 6y2
(ii) (x2 – 2x2) – 23(x2 – 2x) + 120
Answer :
(i) (x + 4)2 – 5xy -20y – 6y2
Above terms can be written as,
(x + 4)2 – 5y(x + 4) – 6y2
(x + 4)2 – 6y(x + 4) + y(x + 4) – 6y2
Take out common in all terms we get,
(x + 4) (x + 4 – 6y) + y(x + 4 – 6y)
(x – 6y + 4) (x + 4 + y)
(ii) (x2 – 2x2) – 23(x2 – 2x) + 120
(x2 – 2x2) – 23(x2 – 2x) + 120
Above terms can be written as,
(x2 – 2x)2 – 15(x2 – 2x) – 8(x2 – 2x) + 120
Take out common in all terms we get,
(x2 – 2x) (x2 – 2x – 15) – 8(x2 – 2x – 15)
(x2 – 2x – 15) (x2 – 2x – 8)
More Solutions: