(x2 – 3x) (x2 – 3x + 7) + 10
(x2 – 3x) (x2 – 3x + 7) + 10
Let us assume, (x2 – 3x) = q
q (q + 7) + 10
q2 + 7q + 10
q2 + 5q + 2q + 10
q(q + 5) + 2(q + 5)
(q + 5) (q + 2)
Now, substitute the value of q
(x2 – 3x + 5) (x2 – 3x + 2)
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(x2 – 3x) (x2 – 3x + 7) + 10
Let us assume, (x2 – 3x) = q
q (q + 7) + 10
q2 + 7q + 10
q2 + 5q + 2q + 10
q(q + 5) + 2(q + 5)
(q + 5) (q + 2)
Now, substitute the value of q
(x2 – 3x + 5) (x2 – 3x + 2)