(i) 5x2 + 17xy – 12y2
(ii) x2y2 – 8xy – 48
Answer :
(i) 5x2 + 17xy – 12y2
5x2 + 20xy – 3xy – 12y2
Take out common in all terms we get,
5x(x + 4y) – 3y(x + 4y)
(x + 4y) (5x – 3y)
(ii) x2y2 – 8xy – 48
x2y2 – 8xy – 48
x2y2 – 12xy + 4xy – 48
Take out common in all terms we get,
xy(xy – 12) + 4(xy – 12)
(xy – 12) (xy + 4)
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