(i) x2y2 – xy – 72
(ii) 9x3y + 41x2y2 + 20xy3
Answer :
(i) x2y2 – xy – 72
x2y2 – 9xy + 8xy – 72
Take out common in all terms,
xy(xy – 9) + 8(xy – 9)
(xy – 9) (xy + 8)
(ii) 9x3y + 41x2y2 + 20xy3
9x3y + 41x2y2 + 20xy3
Take out common in all terms,
xy(9x2 + 41xy + y2)
Above terms can be written as,
xy (9x2 + 36xy + 5xy + 20y2)
xy [9x(x + 4y) + 5y(x + 4y)]
xy (x + 4y) (9x + 5y)