x6 + 63x3 – 64
x6 + 63x3 – 64
Above terms can be written as,
x6 + 64x3 – x3 – 64
Take out common in all terms,
x3 (x3 + 64) – 1(x3 + 64)
(x3 + 64) (x3 – 1)
(x3 + 43) (x3 – 13)
We know that, a3 – b3 = (a – b) (a2 + ab + b2) and a3 + b3 = (a + b) (a2 – ab + b2)
So, (x + 4) [x2 – 4x + 42] (x – 1) [x2 + x + 12]
(x + 4) (x2 – 4x + 16) (x – 1) (x2 + x + 1)