Find the coefficient of x2 and x in the product of (x – 3) (x + 7) (x – 4).
Answer :
It is given that
(x – 3) (x + 7) (x – 4)
By further calculation
= x3 + (- 3 + 7 – 4) x2 + [(-3) (7) + 7 × (-4) + (-4) (-3) + (-3) (7) (-4)]
It can be written as
= x3 + 0x2 + (- 21 – 28 + 12) x + 84
So we get
= x3 + 0x2 – 37x + 84
Hence, coefficient of x2 is zero and coefficient of x is – 3.
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