Find the distance of two stones from the foot of the hill.

From the top of a hill, the angles of depression of two consecutive kilometer stones, due east are found to be 30° and 45° respectively. Find the distance of two stones from the foot of the hill.

Solution:

Let A and B be the position of two consecutive kilometre stones.
Then AB = 1 km = 1000m
Let the dIstance BC = x m
∴ Distance AC = (1000 + x) m

A man observes the angles of elevation of the top of a building to be 30°. He walks towards it in a horizontal line through its base. On covering 60 m the angle of elevation changes to 60°. Find the height of the building correct to the nearest me he.

Solution:

Given that
AB is a building CD = 60 m

More Solutions:

• Solve the following trigonometric:
• Evaluate trigonometric:
• Solve trigonometric:
• Solve: (1 + tan A)/sin A + (1 + cot A)/cos A = 2(sec A + cosec A)
• Prove the identity:
• Solve: (sinθ + cosθ)(secθ + cosecθ) = 2 + secθ cosecθ.