Find the height of the tower.

At a point on level ground, the angle, of elevation of a vertical lower is found to be such that its tangent is . On walking 192 m towards the tower, the tangent of the angle is found to be . Find the height of the tower. (1990)

Solution:

Let TR be the tower and P is the point on the
ground such that tan θ =

In the figure, not drawn to scale, TF is a tower. The elevation of T from A is x° where tan x = and AF = 200 m. The elevation of T from B, where AB = 80 m, is y°. Calculate :
(i) The height of the tower TF.
(ii) The angle y, correct to the nearest degree. (1997)

Solution:

Let height of the tower TF = x
tan x = , AF = 200 m, AB = 80 m
(i) In right ∆ATF,

More Solutions:

• Solve the following trigonometric:
• Evaluate trigonometric:
• Solve trigonometric:
• Solve: (1 + tan A)/sin A + (1 + cot A)/cos A = 2(sec A + cosec A)
• Prove the identity:
• Solve: (sinθ + cosθ)(secθ + cosecθ) = 2 + secθ cosecθ.