Find the mean, median and mode.

Find the mean, median, and mode of the following distribution: 8, 10, 7, 6, 10, 11, 6, 13, 10

Solution:

Mean = $\\ \frac { 8+10+7+6+10+11+6+13+10 }{ 2 }$
= $\\ \frac { 81 }{ 9 }$ = 9
Given nos. in ascending order are as follows:
6, 6, 7, 8, 10, 10, 10, 11, 13
Median = $\\ \frac { n+1 }{ 2 }$ th term = $\\ \frac { 9+1 }{ 2 }$ = 5th term = 10
Mode = 10 (having highest frequency 3 times)

Calculate the mean, the median and the mode of the following numbers : 3, 1, 5, 6, 3, 4, 5, 3, 7, 2

Solution:

Arranging in ascending order 1, 2, 3, 3, 3, 4, 5, 5, 6, 7
(i) Mean = $\frac { \sum { { x }_{ i } } }{ n }$
= $\frac { 1+2+3+3+3+4+5+5+6+7 }{ 8 }$
= $\\ \frac { 39 }{ 10 }$
= 3.9
ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 21 Measures of Central Tendency Ex 21.3 Q4.1