If the number x is 3 less than the number y and the sum of the squares of x and y is 29, find the product of x and y.
Answer :
It is given that
x = y – 3 and x2 + y2 = 29
It can be written as
x – y = – 3
By squaring on both sides
(x – y)2 = (-3)2
Expanding using formula
x2 + y2 – 2xy = 9
Substituting the values
29 – 2xy = 9
By further calculation
-2xy = 9 – 29 = – 20
Dividing by 2
xy = – 20/-2 = 10
So we get
xy = 10
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