A (-4, -1), B (-1, 2), and C (a, 5) are the vertices of an isosceles triangle. Find the value of a, given that AB is the unequal side.
Solution:
More Solutions:
- Point (-3, 5) lies in the (a) first quadrant
- The point which lies only-axis at a distance of 5 units.
- The points whose abscissa and ordinate have different signs:
- On plotting the points O (0, 0), A (3, 0), B (3, 4), C (0, 4).
- Which of the following points lie on the graph of the equation :
- The distance of the point P (-4, 3) from the y-axis is:
- The distance between the points A (0, 6) and B (0, -2) is:
- The length of its diagonal is (a) 5 units:
- If the distance between the points (2, -2) and (-1, x):
- The distance between the points (4, p) and (1, 0):