**Find the value of θ (0° < θ < 90°) if:**

(i) cos 63° sec (90° – θ) = 1

(ii) tan 35° cot (90° – θ) = 1.

**Answer :**

**(i)** **cos 63° sec (90° – θ) = 1**

cos 63° = 1/sec(90° – θ)

1/sec θ = cos θ

cos 63° = cos (90° – θ)

90° – θ = 63°

θ = 90° – 63° = 27°

**(ii)** **tan 35° cot (90° – θ) = 1**

tan 35° = 1/cot (90° – θ)

1/cot θ = cos θ

tan 35° = tan (90° – θ)

35° = 90° – θ

θ = 90° – 35°

= 55°

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